(2x^-2/3)-(7x^-1/3)-20=0

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Solution for (2x^-2/3)-(7x^-1/3)-20=0 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^-2)/3-((7*x^-1)/3)-20 = 0

(-7/3)*x^-1+(2*x^-2)/3-20 = 0

2/3*x^-2-7/3*x^-1-20 = 0

t_1 = x^-1

2/3*t_1^2-7/3*t_1^1-20 = 0

2/3*t_1^2-7/3*t_1-20 = 0

DELTA = (-7/3)^2-(-20*2/3*4)

DELTA = 529/9

DELTA > 0

t_1 = ((529/9)^(1/2)+7/3)/(2/3*2) or t_1 = (7/3-(529/9)^(1/2))/(2/3*2)

t_1 = 15/2 or t_1 = -4

t_1 = -4

x^-1+4 = 0

1*x^-1 = -4 // : 1

x^-1 = -4

-1 < 0

1/(x^1) = -4 // * x^1

1 = -4*x^1 // : -4

-1/4 = x^1

x = -1/4

t_1 = 15/2

x^-1-15/2 = 0

1*x^-1 = 15/2 // : 1

x^-1 = 15/2

-1 < 0

1/(x^1) = 15/2 // * x^1

1 = 15/2*x^1 // : 15/2

2/15 = x^1

x = 2/15

x in { -1/4, 2/15 }

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